Twins Paradox Calculations
Added 2016-08-30 18:31:20 +0000 UTCHere's a full pdf (attached below) of my notes & calculations for the twins paradox resolution video, ranging from just general calculations/trying to remind myself of things/re-deriving for the video, to actually trying to decide what specific speed to do the calculations for in the video so I could make the space-time diagram accurately (see the last page – the magic number turned out to be 60% the speed of light).
Comments
this illustration: <a href="https://en.wikipedia.org/wiki/File:Rstd4.gif" rel="nofollow noopener" target="_blank">https://en.wikipedia.org/wiki/File:Rstd4.gif</a> which is on this wikipedia page: <a href="https://en.wikipedia.org/wiki/Twin_paradox" rel="nofollow noopener" target="_blank">https://en.wikipedia.org/wiki/Twin_paradox</a>#What_it_looks_like:_the_relativistic_Doppler_shift
Henry Reich
2016-08-31 17:46:00 +0000 UTCThis isn't a stupid question at all! There are some great illustrations of this online, like, here, for example:
Henry Reich
2016-08-31 17:45:27 +0000 UTCOK, stupid question time. First, assume A is stationary, and B is flying away. Further assume A is sending B tick-tock at the speed of light (lasers, whatever). As B flies away from A, B's clock slows down due to acceleration. However, B see's the ticks from A slow down, so he thinks A's clock is slowing down instead of his own. Then when B turn around (more acceleration), B sees A's clock ... speed up? So for those 3.6s in the middle, is B getting tons of ticks from A? What's more, when B is on his way back to A, doesn't he see A's clock tick -faster- than his own? He's intercepting the ticks more frequently as the distance closes. Sorry if I am not making sense. If this is too much of your time to explain I'll sit in a corner and think some more....
Patrick W. Gilmore
2016-08-30 18:50:04 +0000 UTC
